Grid Recyclerview，偶数行中有3列，奇数行中有4列(Grid Recyclerview with 3 columns in even number row and 4 columns

Grid Recyclerview，偶数行中有3列，奇数行中有4列(Grid Recyclerview with 3 columns in even number row and 4 columns in odd number row)

如何创建一个Grid Recyclerview，其中偶数行为3列，奇数行为4列？

lLayout = new GridLayoutManager(getActivity(), 4, LinearLayoutManager.VERTICAL, false); // MAX NUMBER OF SPACES lLayout.setSpanSizeLookup(new GridLayoutManager.SpanSizeLookup() { @Override public int getSpanSize(int position) { return (position % 3 == 0 ? 3 : 4); } }); recyclerView = (RecyclerView) view.findViewById(R.id.recyclerView); recyclerView.setLayoutManager(lLayout); if (arrayList != null) { adapter = new RecyclerViewAdapter(getActivity(), arrayList); recyclerView.setAdapter(adapter); }

How to create a Grid Recyclerview with 3 columns in even number row and 4 columns in odd number row?

lLayout = new GridLayoutManager(getActivity(), 4, LinearLayoutManager.VERTICAL, false); // MAX NUMBER OF SPACES lLayout.setSpanSizeLookup(new GridLayoutManager.SpanSizeLookup() { @Override public int getSpanSize(int position) { return (position % 3 == 0 ? 3 : 4); } }); recyclerView = (RecyclerView) view.findViewById(R.id.recyclerView); recyclerView.setLayoutManager(lLayout); if (arrayList != null) { adapter = new RecyclerViewAdapter(getActivity(), arrayList); recyclerView.setAdapter(adapter); }

最满意答案

尝试这个，

// Create a grid layout with 12 columns // (least common multiple of 3 and 4) GridLayoutManager manager = new GridLayoutManager(this, 12, GridLayoutManager.VERTICAL, false); manager.setSpanSizeLookup(new GridLayoutManager.SpanSizeLookup() { @Override public int getSpanSize(int position) { // 7 is the sum of items in one repeated section switch (position % 7) { // first three items span 3 columns each case 0: case 1: case 2: return 4; // next four items span 2 columns each case 3: case 4: case 5: case 6: return 3; } throw new IllegalStateException("internal error"); } }); recyclerView.setLayoutManager(manager);

Try this,

// Create a grid layout with 12 columns // (least common multiple of 3 and 4) GridLayoutManager manager = new GridLayoutManager(this, 12, GridLayoutManager.VERTICAL, false); manager.setSpanSizeLookup(new GridLayoutManager.SpanSizeLookup() { @Override public int getSpanSize(int position) { // 7 is the sum of items in one repeated section switch (position % 7) { // first three items span 3 columns each case 0: case 1: case 2: return 4; // next four items span 2 columns each case 3: case 4: case 5: case 6: return 3; } throw new IllegalStateException("internal error"); } }); recyclerView.setLayoutManager(manager);