ruby如果散列键包含文本，则返回散列键(ruby if hash keys include text, return hash key)

ruby如果散列键包含文本，则返回散列键(ruby if hash keys include text, return hash key)

我有这样的哈希：

hash = {2013 => 'one', 2014 => 'two'}

和一个可变number ：

number = 13

我需要搜索所有的哈希键，如果键中包含number ，我需要返回该键。 现在我有这个：

if hash.keys.any? {|k| k.include? number} #do some work end

这是有效的，但实际上我需要在k确实包含number的情况下返回k ，而不仅仅是检查它。 如何以上面的块“if”格式轻松编写。

I have a hash like so:

hash = {2013 => 'one', 2014 => 'two'}

and a variable number:

number = 13

I need to search through all of my hash keys and if number is included in a key, I need to return that key. Right now I have this:

if hash.keys.any? {|k| k.include? number} #do some work end

That works, but I actually need to return k in the case that k does include number, not just check for it. How can I write that easily in a block "if" format like above.

最满意答案

使用find ：

if result = hash.keys.find {|k| k.include? number} #do some work end

Use find:

if result = hash.keys.find {|k| k.include? number} #do some work end