GNU Make中的双文本替换(double text substituion in GNU Make)

GNU Make中的双文本替换(double text substituion in GNU Make)

假设我有这样的源文件列表。

SRCS = A/src/A1.c A/src/A2.c B/src/B1.c B/src/B2.c

我想从上面的列表中找到对象文件列表。

OBJS = A/obj/A1.o A/obj/A2.o B/obj/B1.o B/obj/B2.o

我想写这样的东西。

OBJS = $(SRCS: %1/src/%2 = %1/obj/%2)

但由于GNU make中没有提供此功能，我需要考虑解决方法。 目前我正在使用它。

SRCS = $(foreach DIR, A B, $(wildcard $(DIR)/src/*.c)) OBJS = $(foreach DIR, A B, $(addprefix $(DIR)/obj/, $(patsubst %.c, %.o, $(notdir $(wildcard $(DIR)/src/*.c)) ) ) ) 删除旧目录名称 替代 附加新的目录名称

但这种方式显然很复杂，所以我想要一个更好的解决方案。 有人知道更好的解决方案吗？

suppose I have source file list like this.

SRCS = A/src/A1.c A/src/A2.c B/src/B1.c B/src/B2.c

I want objects file list from above list.

OBJS = A/obj/A1.o A/obj/A2.o B/obj/B1.o B/obj/B2.o

I want to write something like this.

OBJS = $(SRCS: %1/src/%2 = %1/obj/%2)

But since this feature is not provided in GNU make, I need to think up workaround. Currently I'm using this.

SRCS = $(foreach DIR, A B, $(wildcard $(DIR)/src/*.c)) OBJS = $(foreach DIR, A B, $(addprefix $(DIR)/obj/, $(patsubst %.c, %.o, $(notdir $(wildcard $(DIR)/src/*.c)) ) ) ) remove old dir name do substitution append new dir name

But this way is obviously complicated so I want a better solution. Anyone know better solution to this?

最满意答案

我会用这个：

OBJS := $(subst /src/,/obj/,$(SRCS))

然后修复后缀：

OBJS := $(patsubst %.c,%.o, $(subst /src/,/obj/,$(SRCS)))

I would use this:

OBJS := $(subst /src/,/obj/,$(SRCS))

And then fix the suffix:

OBJS := $(patsubst %.c,%.o, $(subst /src/,/obj/,$(SRCS)))