只有当它们不包含在子字符串中时才用正则表达式分隔空格(split spaces with a regex only if they are not contained in a substring)

只有当它们不包含在子字符串中时才用正则表达式分隔空格(split spaces with a regex only if they are not contained in a substring)

我应该用空格（或\ r \ n \ t）分割一个可能包含子串的字符串

例：

text 'contained in' a string

我试过像正则表达式：

/[?<!\"\'](\ )*[?!\"\']/g;

string.split（regex）应该返回：

["text", "'contained in'", "a", "string"]

。

但这是错的......我在很长时间内解决这个问题：@

现在，我创建了一个split函数，如果有超出子串的话，会自动用sepchar分割，但是我正在寻找一个带正则表达式的简单解决方案，如果可能的话，显然：P

I should split by spaces (or \r\n\t) a string that could contains substrings

Example:

text 'contained in' a string

I have tried with a regex like:

/[?<!\"\'](\ )*[?!\"\']/g;

string.split(regex) should returns:

["text", "'contained in'", "a", "string"]

.

But it's wrong... I'm freaking from much time to resolve it :@

For now, I made a split function that automatically split by a sepchar if there are out of substrings, but I'm looking for a simple solution with regex, if possible, obviously :P

最满意答案

你可以这样做：

(?:'(.*)'|(\b[\w]+\b))

工作正则表达式示例：

http://regex101.com/r/oJ2nQ9

或者甚至更好，而不是使用单词bounderies（因为你的字符串可能包含特殊字符）..这会更好：

(?:'(.*?)'|(?:[\s]*|^)([^\s]+)(?:[\s]*|$))

样本字符串：

text 'contained in' a string-with special's chars.

火柴：

"text", "contained in", "a", "string-with", "special's", "chars."

工作正则表达式示例：

http://regex101.com/r/iP3iJ1

You could do this:

(?:'(.*)'|(\b[\w]+\b))

Working regex example:

http://regex101.com/r/oJ2nQ9

Or even better, rather than using word bounderies (because your string may contain special characters).. This would be better:

(?:'(.*?)'|(?:[\s]*|^)([^\s]+)(?:[\s]*|$))

Sample string:

text 'contained in' a string-with special's chars.

Matches:

"text", "contained in", "a", "string-with", "special's", "chars."

Working regex example:

http://regex101.com/r/iP3iJ1