使用cElementTree来解析属性(Using cElementTree to parse attributes)

使用cElementTree来解析属性(Using cElementTree to parse attributes)

我正在学习cElementTree，我的XML看起来像这样....我试图获得“更新”的文本（我可以！）和“链接”节点中的“href”的属性值（我不能）。

<feed> <entry> <link href="http://www.mondocars.com/0001127602.htm"/> <updated>2017-04-19T13:10:24-04:00</updated> </entry> </feed>

我的代码解析它看起来像这样...

for entry in root.findall('entry'): updated = entry.find('updated').text print updated for link in root.findall('link'): href = link.get('href').attrib print updated, href

href值完全没有被拉动。 我相信这可能是一个不必要的第二个循环。 更新填充罚款，但我不知道如何获得href值。 任何人遇到这个？

提前谢谢了。 珍妮

I am learning cElementTree and my XML looks like this.... I am trying to obtain the "updated" text ( which I can! ) and the attribute value of "href" in the "link" node ( which I can't ).

<feed> <entry> <link href="http://www.mondocars.com/0001127602.htm"/> <updated>2017-04-19T13:10:24-04:00</updated> </entry> </feed>

My code to parse it looks like this...

for entry in root.findall('entry'): updated = entry.find('updated').text print updated for link in root.findall('link'): href = link.get('href').attrib print updated, href

href value isn't being pulled at all. I am convinced that it's probably an unnecessary 2nd for loop. updated populates fine but I can't figure out how to get the href value. Anyone encounter this?

Many thanks in advance. Janie

最满意答案

for entry in root.findall('entry'): updated = entry.find('updated').text href = entry.find('link').attrib.get('href') print updated,href

是正确的方法。

for entry in root.findall('entry'): updated = entry.find('updated').text href = entry.find('link').attrib.get('href') print updated,href

is the correct way.