在字典中压缩两个列表但在密钥中保留重复(Zip two lists in dictionary but keep duplicates in key)

在字典中压缩两个列表但在密钥中保留重复(Zip two lists in dictionary but keep duplicates in key)

我有两个清单：

alist = ['key1','key2','key3','key3','key4','key4','key5'] blist= [30001,30002,30003,30003,30004,30004,30005]

我想合并这些列表并将它们添加到字典中。

我尝试dict(zip(alist,blist))但这给出了：

{'key3'：30003，'key2'：30002，'key1'：30001，'key5'：30005，'key4'：30004}

所需的字典形式是：

{'key1'：30001，'key2'：30002，'key3'：30003，'key3'：30003，'key4'：30004，'key4'：30004，'key5'：30005}

我想保留字典中的重复项以及不在同一个键中加入值（... key3'：30003，'key3'：30003，...）。这可能吗？

提前致谢。

I have two lists:

alist = ['key1','key2','key3','key3','key4','key4','key5'] blist= [30001,30002,30003,30003,30004,30004,30005]

I want to merge these lists and add them to a dictionary.

I try dict(zip(alist,blist)) but this gives:

{'key3': 30003, 'key2': 30002, 'key1': 30001, 'key5': 30005, 'key4': 30004}

The desired form of the dictionary is:

{'key1': 30001, 'key2': 30002, 'key3': 30003,'key3':30003, 'key4': 30004, 'key4': 30004, 'key5': 30005}

I want to keep the duplicates in the dictionary as well as not join the values in the same key (... key3': 30003,'key3':30003,... ).Is it possible?

Thanks in advance.

最满意答案

您不能这样做，因为dict对象具有唯一键。 你应该只使用元组的使用列表：

>>> alist = ['key1','key2','key3','key3','key4','key4','key5'] >>> blist= [30001,30002,30003,30003,30004,30004,30005] >>> zip(alist, blist) [('key1', 30001), ('key2', 30002), ('key3', 30003), ('key3', 30003), ('key4', 30004), ('key4', 30004), ('key5', 30005)]

如果要根据键访问所有值，可以使用collections.defaultdict ：

>>> from collections import defaultdict >>> my_dict = defaultdict(list) >>> for k, v in zip(alist, blist): ... my_dict[k].append(v) ... >>> my_dict defaultdict(<type 'list'>, {'key3': [30003, 30003], 'key2': [30002], 'key1': [30001], 'key5': [30005], 'key4': [30004, 30004]})

您可以访问类似于普通dict对象的defaultdict 。 例如：

>>> my_dict['key3'] [30003, 30003]

You can not do that as dict objects have unique keys. You should just the use list of tuple:

>>> alist = ['key1','key2','key3','key3','key4','key4','key5'] >>> blist= [30001,30002,30003,30003,30004,30004,30005] >>> zip(alist, blist) [('key1', 30001), ('key2', 30002), ('key3', 30003), ('key3', 30003), ('key4', 30004), ('key4', 30004), ('key5', 30005)]

If you want to access all the values based on the key, you may use collections.defaultdict as:

>>> from collections import defaultdict >>> my_dict = defaultdict(list) >>> for k, v in zip(alist, blist): ... my_dict[k].append(v) ... >>> my_dict defaultdict(<type 'list'>, {'key3': [30003, 30003], 'key2': [30002], 'key1': [30001], 'key5': [30005], 'key4': [30004, 30004]})

You can access defaultdict similar to normal dict objects. For example:

>>> my_dict['key3'] [30003, 30003]