Mockery测试构造函数调用，新关键字(Mockery testing constructor call, new keyword)

Mockery测试构造函数调用，新关键字(Mockery testing constructor call, new keyword)

我有一个类名作为字符串属性。 一个方法（ fetchObject ）创建此类的新实例。 我想用PHPUnit和Mockery测试这个方法。

那是代码

class Maker { private $_className = 'Article'; public function fetchObject( $array ) { return new $this->_className( $array ); } }

我试过这样的事

$data = array( 'title' => 'Amazing title' ); $article = m::mock( 'Article', array( $data ) ); $maker= new Maker; $result = $maker->fetchObject( array() );

测试工作，但我不确定它是否检查构造函数调用，我不知道如何检查param是否通过。

I have a class name as a string property. One method (fetchObject) creates new instance of this class. I would like to test this method with PHPUnit and Mockery.

That's the code

class Maker { private $_className = 'Article'; public function fetchObject( $array ) { return new $this->_className( $array ); } }

I tried something like this

$data = array( 'title' => 'Amazing title' ); $article = m::mock( 'Article', array( $data ) ); $maker= new Maker; $result = $maker->fetchObject( array() );

Test works but I'm not sure if it checks for constructor call and I don't know how to check if param was passed.

最满意答案

通常你会模拟Maker（）类，并确保它从mock，你正在寻找的对象返回。

我为测试这样的事情做的另一个选择是简单地测试Maker并使用给定的类期望调用fetchObject（）例程，然后使用InstanceOf检查返回的对象是否是所需的类。

Normally you would mock the Maker() class, and ensure it returned from the mock, the object you are looking for.

The other option I have done to test things like this, is to simply test Maker and call the fetchObject() routine with a given class expectation, and then test with an InstanceOf check that the returned object is of the desired class.