如何将对象作为参数传递给函数？(How to pass object as paramaters to function?)

如何将对象作为参数传递给函数？(How to pass object as paramaters to function?)

我有功能的定义：

def setup(self, **kwargs): pass

并称之为：

params = { "advert_id": adv_id, "enabled": True, "from_hour": 2, "to_hour": 1, "interval": 0, "weekdays": [1] } setup(params)

我试图将params作为对象传递，但它不起作用。 我知道正确的方法是：

setup(advert_id=1,enabled=True,from_hour=3,to_hour=4,interval=0,weekdays=[])

无论如何，我不想枚举所有参数，并希望将其打包到对象。

I have defination of function:

def setup(self, **kwargs): pass

And calling this like:

params = { "advert_id": adv_id, "enabled": True, "from_hour": 2, "to_hour": 1, "interval": 0, "weekdays": [1] } setup(params)

I tried to pass params as object, but it does not work. I know correct way is:

setup(advert_id=1,enabled=True,from_hour=3,to_hour=4,interval=0,weekdays=[])

Anyway I don't want to enumerate all parameters and want to pack it to object.

最满意答案

解压缩函数调用中的参数：

def setup(self, **kwargs): pass params = { "advert_id": adv_id, "enabled": True, "from_hour": 2, "to_hour": 1, "interval": 0, "weekdays": [1] } setup(**params)

Unpack params in the function call:

def setup(self, **kwargs): pass params = { "advert_id": adv_id, "enabled": True, "from_hour": 2, "to_hour": 1, "interval": 0, "weekdays": [1] } setup(**params)