成功登录后转到另一页面(Pass to another page after successfully login)

成功登录后转到另一页面(Pass to another page after successfully login)

我想在登录后去另一个页面，所以如何在使用Ajax和php成功登录后传递到另一个页面？ 当ajax向php发送请求然后得到响应时（如果响应是（'true'）或（'false'）这个响应取决于检查用户名和密码）所以我不知道如何处理这个响应在ajax中使用它作为传递到下一页的条件。 请帮忙。

var HttPRequest = false; function doCallAjax(Mode) { HttPRequest = false; if (window.XMLHttpRequest) { // Mozilla, Safari,... HttPRequest = new XMLHttpRequest(); if (HttPRequest.overrideMimeType) { HttPRequest.overrideMimeType('text/html'); } } else if (window.ActiveXObject) { // IE try { HttPRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { HttPRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) {} } } if (!HttPRequest) { alert('Cannot create XMLHTTP instance'); return false; } var url = 'PHP_Login.php'; var pmeters = "tEmail=" + encodeURI( document.getElementById("Email").value) + "&tpassword=" + encodeURI( document.getElementById("password").value ) + "&tMode=" + Mode; HttPRequest.open('POST',url,true); HttPRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); HttPRequest.setRequestHeader("Content-length", pmeters.length); HttPRequest.setRequestHeader("Connection", "close"); HttPRequest.send(pmeters); HttPRequest.onreadystatechange = function() { if(HttPRequest.readyState == 3) // Loading Request { document.getElementById("mySpan").innerHTML = "Now is Loading..."; } if(HttPRequest.readyState == 4) // Return Request { document.getElementById("mySpan").innerHTML = HttPRequest.responseText; document.getElementById("Email").value = ''; document.getElementById("password").value = ''; } } }

I am trying to go to another page after login so How can I pass to another page after successfully login using Ajax and php ? when ajax send a request to php and then get the response like (if the response is ('true') or ('false') this responses depends on checking the username and password) so i do not know how to deal with this response in ajax to use it as a condition to pass to the next page. please help.

var HttPRequest = false; function doCallAjax(Mode) { HttPRequest = false; if (window.XMLHttpRequest) { // Mozilla, Safari,... HttPRequest = new XMLHttpRequest(); if (HttPRequest.overrideMimeType) { HttPRequest.overrideMimeType('text/html'); } } else if (window.ActiveXObject) { // IE try { HttPRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { HttPRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) {} } } if (!HttPRequest) { alert('Cannot create XMLHTTP instance'); return false; } var url = 'PHP_Login.php'; var pmeters = "tEmail=" + encodeURI( document.getElementById("Email").value) + "&tpassword=" + encodeURI( document.getElementById("password").value ) + "&tMode=" + Mode; HttPRequest.open('POST',url,true); HttPRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); HttPRequest.setRequestHeader("Content-length", pmeters.length); HttPRequest.setRequestHeader("Connection", "close"); HttPRequest.send(pmeters); HttPRequest.onreadystatechange = function() { if(HttPRequest.readyState == 3) // Loading Request { document.getElementById("mySpan").innerHTML = "Now is Loading..."; } if(HttPRequest.readyState == 4) // Return Request { document.getElementById("mySpan").innerHTML = HttPRequest.responseText; document.getElementById("Email").value = ''; document.getElementById("password").value = ''; } } }

最满意答案

要在PHP中重定向到不同的页面使用

header("Location: http://example.com/success.html");

To redirect to a different page in PHP use

header("Location: http://example.com/success.html");