Php检查数组中是否存在具有属性的对象(Php check if object with property exists in array)

Php检查数组中是否存在具有属性的对象(Php check if object with property exists in array)

假设我有以下PHP代码：

$a = new a(); $a->id = 1;

然后我有一个数组$m类型为a的对象（但它们实际上可以是任何类型）。 我想检查m中的任何对象是否具有等于1的属性id。在Java中，我会执行以下操作：

myList .stream() .filter(x <- x.id == a.id) .count();

在PHP中我试过了

in_array($a, $m)

但这似乎没有起作用，因为很明显即使另一个对象具有相同的ID，它仍然是一个不同的对象。

我显然可以使用一个循环，但实际上我想检查数组中的任何对象是否有一个具有相同ID的相应对象，我宁愿避免嵌套循环。

Let's assume I have the following PHP code:

$a = new a(); $a->id = 1;

I then have an array $m of objects of type type a (but they really could be of any type). I want to check if any object in m has property id equal to 1. In Java, I'd do something like:

myList .stream() .filter(x <- x.id == a.id) .count();

In PHP I tried

in_array($a, $m)

but that didn't seem to do work, because obviously even if another object had the same ID it would still be a different object.

I could obviously use a loop, but as really I'd want to check if any object in an array n had a corresponding object with the same ID in m I'd rather avoid a nested loop.

最满意答案

PHP还有一个数组过滤功能，它（由于显而易见的原因）被称为array_filter（）并使用匿名函数执行您想要的操作。

function findAllWithId($objects, $id) { return array_filter($objects, function($toCheck) use ($id) { return $toCheck->id == $id; }); }

PHP also has an array filtering functioning, which (for obvious reasons) is called array_filter() and does what you want, with anonymous functions.

function findAllWithId($objects, $id) { return array_filter($objects, function($toCheck) use ($id) { return $toCheck->id == $id; }); }