返回URL的特定部分(return specific part of URL)

我希望通过php返回URL的特定部分。 例如，如果URL是：

http://website.com/part1/part2/part3/detail/page_id/number/page/2
 
 要么 
 
http://website.com/part1/part2/part3/detail/page_id/number/page/3 
 
 我想要退货号码。 
 
 好吗？ 
 
$pattern = "/\d+$/";
$input = "http://website.com/part1/part2/part3/detail/page_id/number/page/2";
preg_match($pattern, $input, $matches);
$post_id = $matches[8];
I want return specific part of URL by php. for example if URL is :
 
http://website.com/part1/part2/part3/detail/page_id/number/page/2
 
or 
 
http://website.com/part1/part2/part3/detail/page_id/number/page/3 
 
I want return number.
 
is it okay?
 
$pattern = "/\d+$/";
$input = "http://website.com/part1/part2/part3/detail/page_id/number/page/2";
preg_match($pattern, $input, $matches);
$post_id = $matches[8];

                
最满意答案
                
                    
                        
 我认为id会在$matches[0] 。 但是这个正则表达式模式会匹配最后一个数字的任何url。 例如 
 
http://differentdomain.com/whatever/7
 
 也许这对你来说已经足够了，如果没有，请更详细地描述你的用例。 
use it: 
 
return $id3 = $parts[count($parts) - 3];