从Python中的字符串中除去所有非数字字符（“。”除外）(Strip all non

从Python中的字符串中除去所有非数字字符（“。”除外）(Strip all non-numeric characters (except for “.”) from a string in Python)

我有一个非常好的工作代码，但我想知道是否有任何更好的建议如何做到这一点：

val = ''.join([c for c in val if c in '1234567890.'])

你会怎么做？

I've got a pretty good working snippit of code, but I was wondering if anyone has any better suggestions on how to do this:

val = ''.join([c for c in val if c in '1234567890.'])

What would you do?

最满意答案

您可以使用正则表达式（使用re模块）来完成相同的事情。 下面的示例匹配运行的[^\d.] （任何不是十进制数字或句点的字符），并用空字符串替换它们。 请注意，如果使用UNICODE标志编译模式，则生成的字符串仍可能包含非ASCII数字 。 此外，删除“非数字”字符后的结果不一定是有效的数字。

>>> import re >>> non_decimal = re.compile(r'[^\d.]+') >>> non_decimal.sub('', '12.34fe4e') '12.344'

You can use a regular expression (using the re module) to accomplish the same thing. The example below matches runs of [^\d.] (any character that's not a decimal digit or a period) and replaces them with the empty string. Note that if the pattern is compiled with the UNICODE flag the resulting string could still include non-ASCII numbers. Also, the result after removing "non-numeric" characters is not necessarily a valid number.

>>> import re >>> non_decimal = re.compile(r'[^\d.]+') >>> non_decimal.sub('', '12.34fe4e') '12.344'