以ISO 8601格式输出日期(Outputting date in ISO 8601 format)

以ISO 8601格式输出日期(Outputting date in ISO 8601 format)

我如何在C ++中使用以下格式获取日期：

2016-04-26T19:50:48Z #include <chrono> #include <ctime> time_t _tm = time(NULL); struct tm*curtime = localtime(&_tm);

并输出asctime(curtime)

目前的输出是： "Thu Apr 28 16:02:41 2016\n"

How can I get a date in the following format in C++:

2016-04-26T19:50:48Z #include <chrono> #include <ctime> time_t _tm = time(NULL); struct tm*curtime = localtime(&_tm);

And outputting as asctime(curtime)

The current output is: "Thu Apr 28 16:02:41 2016\n"

最满意答案

文档是你的朋友：

std::time_t t = std::chrono::system_clock::to_time_t(std::chrono::system_clock::now()); std::cout << std::put_time( std::localtime( &t ), "%FT%T%z" );

在我的系统产量

2016-04-29T02:48:56+0200

Documentation is your friend:

std::time_t t = std::chrono::system_clock::to_time_t(std::chrono::system_clock::now()); std::cout << std::put_time( std::localtime( &t ), "%FT%T%z" );

in my system yields

2016-04-29T02:48:56+0200