打印，循环，缩进，Python(Print, loop, Indentation, Python)

打印，循环，缩进，Python(Print, loop, Indentation, Python)

我需要一点帮助。 我目前正在学习python，我有python 2.7.8我正在寻找一个简单的程序来帮助计算我的单词中的元音。 这是代码：

count = 0 total = 0 for v in "bonbon": count += 1 if v == 'e' or v == 'o' or v == 'u' or v == 'a': print('the number of vowel in your word is ' +str(total))

为什么要打印两次？ 1-我的元音数是0，然后我的数是2

有人可以帮帮我吗？ 多谢你们

I need a pit of help. I am currently learning python, and I have python 2.7.8 I am looking to build a simple program that will help to count the vowels in my word. Here is the code:

count = 0 total = 0 for v in "bonbon": count += 1 if v == 'e' or v == 'o' or v == 'u' or v == 'a': print('the number of vowel in your word is ' +str(total))

Why does it print twice? 1- the number of my vowel is 0 and then the number of my is 2

Could someone help me please? Thanks guys

最满意答案

它打印两次，因为你在for循环中有打印。 您应该在for循环内增加total，然后再打印它。 如果你这样做：

count = 0 total = 0 for v in "bonbon": count += 1 if v == 'e' or v == 'o' or v == 'u' or v == 'a': total += 1 print('the number of vowel in your word is ' + str(total))

它应该工作。

It's printing twice because you have the print inside of the for loop. You should instead increment total inside the for loop and then print it afterwards. If you do:

count = 0 total = 0 for v in "bonbon": count += 1 if v == 'e' or v == 'o' or v == 'u' or v == 'a': total += 1 print('the number of vowel in your word is ' + str(total))

It should work.