如何在C ++中列出长度为12的所有字符串？(How to list all strings of length 12 in C++?)

我是一个研究自己的新手程序员。我试图创建一个程序，列出长度为12的所有字符串，例如字符来自az。但是，似乎有一个我能找到的错误。它输出例如The word is ). 任何人都可以告诉我我做错了什么，有没有更简单的方法来执行该程序？

#include <iostream> #include <string> int main(int argc, char *argv[]) { using namespace std; string l ("qwertyuiopasdfghjklzxcvbnm"); string test (""); for(int i1 = 0;i1 < 26;++i1) for(int i2 = 0;i2 < 26;++i2) for(int i3 = 0;i3 < 26;++i3) for(int i4 = 0;i4 < 26;++i4) for(int i5 = 0;i5 < 26;++i5) for(int i6 = 0;i6 < 26;++i6) for(int i7 = 0;i7 < 26;++i7) for(int i8 = 0;i8 < 26;++i8) for(int i9 = 0;i9 < 26;++i9) for(int i10 = 0;i10 < 26;++i10) for(int i11 = 0;i11 < 26;++i11) for(int i12 = 0;i12 < 26;++i12) { test = l[i1]+l[i2]+l[i3]+l[i4]+l[i5]+l[i6]+l[i7]+l[i8]+l[i9]+l[i10]+l[i11]+l[i12]; cout << "The word is " << test << "." << endl; test = ""; } return 0; }

I'm a novice programmer studying my own. I tried to make a program that lists all strings of length 12 such as its characters are from a-z. However, there seems to be a bug I could find. It outputs for example The word is ). Could anyone tell me what I'm doing wrong, and is there some easier way to do the program?

#include <iostream> #include <string> int main(int argc, char *argv[]) { using namespace std; string l ("qwertyuiopasdfghjklzxcvbnm"); string test (""); for(int i1 = 0;i1 < 26;++i1) for(int i2 = 0;i2 < 26;++i2) for(int i3 = 0;i3 < 26;++i3) for(int i4 = 0;i4 < 26;++i4) for(int i5 = 0;i5 < 26;++i5) for(int i6 = 0;i6 < 26;++i6) for(int i7 = 0;i7 < 26;++i7) for(int i8 = 0;i8 < 26;++i8) for(int i9 = 0;i9 < 26;++i9) for(int i10 = 0;i10 < 26;++i10) for(int i11 = 0;i11 < 26;++i11) for(int i12 = 0;i12 < 26;++i12) { test = l[i1]+l[i2]+l[i3]+l[i4]+l[i5]+l[i6]+l[i7]+l[i8]+l[i9]+l[i10]+l[i11]+l[i12]; cout << "The word is " << test << "." << endl; test = ""; } return 0; }