我有一个下拉列表，其中包含城镇选项''Bury''和''Ipswich''，如下所示： 。 选择时其中一个选项，其值传递给变量 $ townsearch。 如何更改下拉列表以便上次选择的选项为 然后是下拉框中显示的当前值？ < body> <？php $ townsearch = $ _get [ '' 镇 '']; ？> < form action ="<？php echo $ _SERVER [''PHP_SELF'']; ？>" method =" get"> < select size =" 1" name =" town"> < option> ipswich< / option> < option> bury< / option> & nbsp; < / select>& nbsp; < input type =" submit"值= QUOT; GO" /> < / form> 非常感谢 Alec
I have a drop down list with the town options ''Bury'' and ''Ipswich'' as shown below. When selecting one of the options, its value is passed to variable $townsearch. How do I change the drop down list so the option selected last time is then the current one shown in the drop down box? <body> <?php $townsearch = $_get[''town'']; ?> <form action="<?php echo $_SERVER[''PHP_SELF'']; ?>" method="get"> <select size="1" name="town"> <option>ipswich</option> <option>bury</option> </select> <input type="submit" value="GO" /> </form> Many thanks Alec
推荐答案townsearch。 如何更改下拉列表以便上次选择该选项是 然后下拉框中显示当前的那个？ < body> <？php townsearch. How do I change the drop down list so the option selected last time is then the current one shown in the drop down box? <body> <?php
townsearch = townsearch =
_get [''town'']; ？> < form action ="<？php echo _get[''town'']; ?> <form action="<?php echo
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