C语言的FastCGI与Nginx的

本文介绍了C语言的FastCGI与Nginx的的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我试图运行用Nginx的网络服务器后面C语言的FastCGI应用程序。 Web浏览器永远不会完成加载和响应永远不会完成。我不知道如何处理它和调试。任何有识之士将AP preciated。

Hello World应用程序从fastcgi抽取并简化看起来是这样的：

的#includefcgi_stdio.h＃包括LT＆;＆stdlib.h中GT;INT主要（无效）{ 而（FCGI_Accept将＆GT; = 0） {  的printf（内容类型：text / html的\\ r \\ n状态：200 OK \\ r \\ n \\ r \\ n）; }  返回0;}

输出的可执行文件与任何一个执行：

  

CGI-FCGI -connect 127.0.0.1:9000的a.out

或

  

产卵-FCGI -a120.0.0.1 -p9000 -n ./a.out

Nginx的配置是：

服务器{        听80;        服务器名称 _; 位置 / {                        ＃主机和端口的FastCGI服务器                        根/ home / user中/ WWW;                        指数的index.html;                        fastcgi_pass 127.0.0.1:9000; }}

解决方案

您需要调用 FCGI_Accept将在，而循环：

而（FCGI_Accept将（）＆GT; = 0）

您有 FCGI_Accept将＆GT; = 0 在code。我认为，导致 FCGI_Accept将函数的地址进行比较，以 0 。由于功能存在，该比较是从未假的，但不被调用的功能。

I am attempting to run a fastcgi app written in C language behind the Nginx web server. The web browser never finishes loading and the response never completes. I am not sure how to approach it and debug. Any insight would be appreciated.

The hello world application was taken from fastcgi and simplified to look like this:

#include "fcgi_stdio.h" #include <stdlib.h> int main(void) { while(FCGI_Accept >= 0) { printf("Content-type: text/html\r\nStatus: 200 OK\r\n\r\n"); } return 0; }

Output executable is executed with either one of:

cgi-fcgi -connect 127.0.0.1:9000 a.out

or

spawn-fcgi -a120.0.0.1 -p9000 -n ./a.out

Nginx configuration is:

server { listen 80; server_name _; location / { # host and port to fastcgi server root /home/user/www; index index.html; fastcgi_pass 127.0.0.1:9000; } }

解决方案

You need to call FCGI_Accept in the while loop:

while(FCGI_Accept() >= 0)

You have FCGI_Accept >= 0 in your code. I think that results in the address of the FCGI_Accept function being compared to 0. Since the function exists, the comparison is never false, but the function is not being invoked.