我有以下代码
#include <iostream> #include <vector> #include <functional> int main() { std::vector<double> v(5, 10.3); std::vector<double>& r = v; //std::vector<std::reference_wrapper<double>> r(v.begin(),v.end()); for (auto& i : v) i *= 3; for (auto i : r) std::cout << i << " "; std::cout << std::endl; }我使用向量'r'的引用使用'&在第二行我注释掉我使用std :: reference_wrapper的C ++。两个都做同样的工作?但我认为必须有一个目的,使std :: reference_wrapper,即使我们有'&'来完成这项工作。
I am using reference of the vector 'r' using '&' operator and in the second line which I commented out I am using std::reference_wrapper of C++. Both do pretty much the same job? But I think there must be a purpose of making std::reference_wrapper even if we had '&' to do the job. can anyone explain please?
推荐答案首先,两行
std::vector<double>& r = v; std::vector<std::reference_wrapper<double>> r(v.begin(),v.end());不是指同样的事情。
其次,std :: reference_wrapper在通用编程中非常有用(一个是双引号向量的引用,另一个是双引号向量的引用) ie:templates)其中函数可以通过复制获取其参数,但是您仍然希望通过引用传递参数。或者,如果你想要一个容器有引用,但不能使用引用,因为它们不可复制或移动,那么std :: reference_wrapper可以做这项工作。
Second, std::reference_wrapper is useful in generic programming (ie: templates) where either a function might take its arguments by copy, but you still want to pass in an argument by reference. Or, if you want a container to have references, but can't use references because they aren't copyable or movable, then std::reference_wrapper can do the job.
本质上,std :: reference_wrapper的行为就像一个&除非它是可复制和可重新分配的
Essentially, std::reference_wrapper acts like a "&" reference, except that it's copyable and reassignable
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“&”之间的区别,和std :: reference
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