我想序列化另一个包含此向量的对象。一切除了，这个向量序列化了，但一旦到达向量，它会抛出：
终止调用后抛出一个boost :: archive :: archive_exception的实例 what（）：未注册的类派生类未注册或导出我已经尝试了一些事情，包括在序列化之前明确地注册父类型，明确地将基本抽象类声明为BOOST_SERIALIZATION_ASSUME_ABSTRACT等。但是，我离开了除了在运行时间外。
我想将这个例子（和解决方案）记录下来，以便其他人可以使用这个优秀的，如果有点不透明的库。一旦这个例子是平方的，我会将它提交给升级序列化维护者，以包含在他们认为合适的FAQ或文档中。
示例代码来复制问题以下：
/ * g ++ -Iinclude / -Llib -lboost_serialization〜/ Desktop / ser_ex.cpp -o stest * / #include< boost / serialization / serialization.hpp> #include次要修改：
-
替换 ar& bser :: base_object< AA>（* this）; in BB :: serialize with：
ar& BOOST_SERIALIZATION_BASE_OBJECT_NVP（AA）; -
替换 ar& bser :: base_object< BB>（* this）; in CC :: serialize with：
ar& BOOST_SERIALIZATION_BASE_OBJECT_NVP（BB）; -
添加 BOOST_CLASS_EXPORT（CC） CC 定义后。有关说明，请参阅此文档部分 。
i've been reading, cross-referencing, and ultimately not finding a coherent example and answer. what i'm trying to do is pretty simple, but i'm clearly missing something. in english, i've got a class structure with two abstract bases (pure BB derives from pure AA), which i manage as a:
std::vector<AA*>i'd like to serialize another object containing this vector. everything except this vector serializes fine, but once it gets to the vector, it throws:
terminate called after throwing an instance of 'boost::archive::archive_exception' what(): unregistered class - derived class not registered or exportedi've tried a few things, including explicitly registering the parent types prior to serialization, expressly declaring the base abstract classes as such with 'BOOST_SERIALIZATION_ASSUME_ABSTRACT', etc. however, i'm left with the exception at runtime.
i'd like to get this example (and solution) on the record so others can use this excellent, if a little opaque, library. once this example is square, i'll submit it to the boost serialization maintainers to include in either the FAQ or documentation as they see fit.
sample code to replicate the problem below:
/* g++ -Iinclude/ -Llib -lboost_serialization ~/Desktop/ser_ex.cpp -o stest */ #include <boost/serialization/serialization.hpp> #include <boost/serialization/nvp.hpp> #include <boost/archive/xml_oarchive.hpp> #include <boost/serialization/vector.hpp> #include <iostream> #include <fstream> #include <string> #include <vector> namespace bser = boost::serialization; class AA { public: virtual void foo() = 0; std::string name; template<class Archive> void serialize(Archive & ar, unsigned int file_version) { ar & bser::make_nvp( "Name", name ); } }; BOOST_SERIALIZATION_ASSUME_ABSTRACT( AA ); class BB : public AA { public: virtual void foo() = 0; virtual void bar() = 0; int thing; template<class Archive> void serialize(Archive & ar, unsigned int file_version) { ar.template register_type< AA >(); ar & bser::base_object< AA >( *this ); ar & bser::make_nvp( "Thing", thing ); } }; BOOST_SERIALIZATION_ASSUME_ABSTRACT( BB ); class CC : public BB { public: virtual void foo() {} virtual void bar() {} int otherThing; template<class Archive> void serialize(Archive & ar, unsigned int file_version) { ar.template register_type< BB >(); ar & bser::base_object< BB >( *this ); ar & bser::make_nvp( "OtherThing", otherThing ); } }; int main (int argc, char const *argv[]) { const std::string filename( "my.serialized" ); const std::string key( "AAVector" ); std::vector< AA* > vv; vv.push_back( new CC ); std::ofstream outfilestream( filename.c_str(), std::ios::binary ); boost::archive::xml_oarchive out_archive( outfilestream ); out_archive << boost::serialization::make_nvp( key.c_str(), vv ); outfilestream.close(); }解决方案
I got this to work with minor modifications :
Replace ar & bser::base_object< AA >( *this ); in BB::serialize with :
ar & BOOST_SERIALIZATION_BASE_OBJECT_NVP(AA);Replace ar & bser::base_object< BB >( *this ); in CC::serialize with :
ar & BOOST_SERIALIZATION_BASE_OBJECT_NVP(BB);Add a BOOST_CLASS_EXPORT(CC) after CC definition. See this documentation section for an explanation.
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