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问题描述
在示例中
Class Person{ String name; int age; }如果json对象缺少属性'age',
If the json object has a missing property 'age',
{ name : John } Person person = objectMapper.readValue(jsonFileReader, Person.class);它会抛出一个JsonMappingException,说它不能反序列化。是否有注释在反序列化期间忽略缺失的字段?
it throws a JsonMappingException saying it cannot deserialize. Is there an annotation to ignore missing fields during deserialization ?
谢谢
推荐答案我认为你想要的是
@JsonSerialize(include = JsonSerialize.Inclusion.NON_NULL) public class Person { ... }这是Jackson 1.x的方式。我认为在2.x中有一种新的方式。类似
that's the Jackson 1.x way. I think there's a new way in 2.x. Something like
@JsonInclude(Include.NON_NULL) public class Person { ... }这些将告诉Jackson只序列化非空值,不要抱怨反序列化缺失值时。我认为它只会将其设置为Java默认值。
These will tell Jackson to only serialize values that are not null, and don't complain when deserializing a missing value. I think it will just set it to the Java default.
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在java中使用jackson json反序列化时忽略缺少的属性
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