本文介绍了将直方图分为两个区域的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想将直方图分为两个区域(通过获取直方图图像的平均强度值).
I want to divide the histogram into two regions (by taking the avg intensity value of histogram image).
hR = imhist(redChannel); minRed = min(redChannel(:)); maxRed = max(redChannel(:)); avgRed = (minRed+maxRed)/2; hlowR = hR(1:avgRed); hhighR = hR(avgRed:256);hlowR提供值,但hhighR为空.我不知道怎么了请帮忙.谢谢
hlowR is giving the values but hhighR is empty. I don't know what's wrong. Please help. Thanks
推荐答案hR = imhist(redChannel); % minRed = min(redChannel(:)); % maxRed = max(redChannel(:)); % avgRed = (minRed+maxRed)/2; avgRed = mean(redChannel(:)); % get mean directly hlowR = hR(hR<=avgRed); % Logical index to find all values below the average hhighR = hR(hR>=avgRed);% Logical index to find all values above the average
您直接将avgRed用作索引,同时应使用逻辑索引.
You are using avgRed directly as index, whilst you should check whether a value of hR is above or below it, using logical indexing.
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将直方图分为两个区域
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