将嵌套列表分为两个列表

本文介绍了将嵌套列表分为两个列表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个这样的嵌套列表:

I have a nested list like this:

my_list = [[1320120000000, 48596281], [1320206400000, 48596281], [1320292800000, 50447908]]

我想将其拆分为如下所示的内容:

I would like to split it into something that looks like this:

my_list1 = [48596281, 48596281, 50447908] my_list2 = [1320120000000, 1320206400000, 1320292800000]

我知道这很简单，但是我无法使其正常工作.任何帮助将不胜感激.

I know that this is fairly simple, but I haven't been able to get it to work. Any help would be much appreciated.

推荐答案

这是内置函数 zip 用于.

This is what the builtin function zip is for.

my_list2, my_list1 = zip(*my_list)

如果您想要列表而不是元组，则可以

If you want lists instead of tuples, you can do

my_list2, my_list1 = map(list, zip(*my_list))