我有一个 输出一个 组件和由 呈现的联系人列表;.
问题是,在对 的测试中,当我尝试挂载它时,测试输出错误 Invariant Violation: You should not use 或 withRouter() 在 <Router>
之外withRouter() 用于 组件.
如何在没有路由器的情况下模拟 ContactsComponent 来测试父组件?
我发现了一些类似的问题 www.bountysource/issues/49297944-invariant-violation-you-should-not-use-route-or-withrouter-outside-a-router但它只描述了组件被 withRouter() 本身覆盖的情况,而不是子组件.
UserList.test.jsx
const mockResp = {数:2,项目: [{_id: 1,名称:'用户1',电子邮件:'email1@gmail',电话:'+123456',在线:假的},{_id: 2,名称:'用户2',电子邮件:'email2@gmail',电话:'+789123',在线:假的},{_id: 3,名称:'用户3',电子邮件:'email3@gmail',电话:'+258369147',在线:假的}],下一个: 空}描述('用户列表',()=> {beforeEach(() => {fetch.resetMocks()});test('应该输出用户列表', () => {fetch.mockResponseOnce(JSON.stringify(mockResp));const wrapper = mount(<UserListComponent user={mockResp.items[2]}/>);期望(wrapper.find('.contact_small')).to.have.length(3);});})UserList.jsx
export class UserListComponent extends PureComponent {使成为() {const { 用户,错误 } = this.state;返回 (<React.Fragment><联系方式用户名={this.props.user.name}内容={this.props.user.phone}/>{错误 ?<p>{error.message}</p>: <Contacts type="contactList" user={this.props.user} contacts={users}/>}</React.Fragment>);}}Contacts.jsx
class ContactsComponent 扩展组件 {构造函数(){极好的();this.state = {错误:空,};}使成为() {返回 (<React.Fragment><SectionTitle title="联系人"/><div className="联系人">//联系人</React.Fragment>);}}export const Contacts = withRouter(ContactsComponent);
解决方案要测试包含 和 withRouter 的组件(使用 Jest),您需要在您的测试中导入路由器,而不是在您的组件中
import { BrowserRouter as Router } from 'react-router-dom';并像这样使用它
app = 浅(<路由器><应用程序/></路由器>);I have a <UserListComponent /> which outputs one <Contact /> component and list of contacts presentated by <Contacts />.
The problem is that in the test for <UserListComponent /> when I try to mount it, test outputs an error Invariant Violation: You should not use <Route> or withRouter() outside a <Router>
withRouter() is used in <Contacts /> component.
How can I mock ContactsComponent without router in test of parent component?
I found some similar issue www.bountysource/issues/49297944-invariant-violation-you-should-not-use-route-or-withrouter-outside-a-router but it only describes situation when component is cover by withRouter() itself, not children.
UserList.test.jsx
const mockResp = { count: 2, items: [ { _id: 1, name: 'User1', email: 'email1@gmail', phone: '+123456', online: false }, { _id: 2, name: 'User2', email: 'email2@gmail', phone: '+789123', online: false }, { _id: 3, name: 'User3', email: 'email3@gmail', phone: '+258369147', online: false } ], next: null } describe('UserList', () => { beforeEach(() => { fetch.resetMocks() }); test('should output list of users', () => { fetch.mockResponseOnce(JSON.stringify(mockResp)); const wrapper = mount(<UserListComponent user={mockResp.items[2]} />); expect(wrapper.find('.contact_small')).to.have.length(3); }); })UserList.jsx
export class UserListComponent extends PureComponent { render() { const { users, error } = this.state; return ( <React.Fragment> <Contact userName={this.props.user.name} content={this.props.user.phone} /> {error ? <p>{error.message}</p> : <Contacts type="contactList" user={this.props.user} contacts={users} />} </React.Fragment> ); } }Contacts.jsx
class ContactsComponent extends Component { constructor() { super(); this.state = { error: null, }; } render() { return ( <React.Fragment> <SectionTitle title="Contacts" /> <div className="contacts"> //contacts </div> </React.Fragment> ); } } export const Contacts = withRouter(ContactsComponent);解决方案
To test a component (with Jest) that contains <Route> and withRouter you need to import Router in you test, not in your component
import { BrowserRouter as Router } from 'react-router-dom';and use it like this
app = shallow( <Router> <App /> </Router>);
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