如何将long类型转换为String类型？(How to convert type long to type String ? To solve : 'Encode(java.lang.st

如何将long类型转换为String类型？(How to convert type long to type String ? To solve : 'Encode(java.lang.string)' in android.net.Uri cannot be applied to long)

我正在开发一个Android应用程序，其中的数据来自JSON。 我正在通过Baseadapter生成列表视图。 当我点击号码（ TextView ）时，我需要打电话给那个号码。 我试过它如下

//initialization public long abc; in getView(int position, View convertView, ViewGroup parent) { abc = m.getNumber(); number.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Intent out = new Intent(Intent.ACTION_CALL); out.setData(Uri.parse("tel:" + Uri.encode(abc))); context.startActivity(out); } }); return convertView; }

我得到的错误是'Encode(java.lang.string)' in android.net.Uri cannot be applied to long.

其实是什么意思？ 如何解决问题？

I am developing an android app in which the data is taken from JSON. And I am generating the listview through Baseadapter. When I click the number (TextView), I need to make a phone call to that number. I have tried it as follows

//initialization public long abc; in getView(int position, View convertView, ViewGroup parent) { abc = m.getNumber(); number.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Intent out = new Intent(Intent.ACTION_CALL); out.setData(Uri.parse("tel:" + Uri.encode(abc))); context.startActivity(out); } }); return convertView; }

Error I am getting is 'Encode(java.lang.string)' in android.net.Uri cannot be applied to long.

Actually what does it mean? How to solve the problem?

最满意答案

你的abc变量很长。 将其转换为String，因为错误说“android.net.Uri中的Encode（java.lang.string）”不能应用于long“

Intent out = new Intent(Intent.ACTION_CALL); out.setData(Uri.parse("tel:" + Uri.encode(String.valueOf(abc)))); context.startActivity(out);

Your abc variable is long. convert it into String as error saying "Encode(java.lang.string)' in android.net.Uri cannot be applied to long"

Intent out = new Intent(Intent.ACTION_CALL); out.setData(Uri.parse("tel:" + Uri.encode(String.valueOf(abc)))); context.startActivity(out);