如何使用Asp MVC Url Helpers生成RESTful链接？(How do I use Asp MVC Url Helpers to generate RESTful links?)

编程入门行业动态更新时间:2024-10-26 15:16:46

我正在尝试使用Html.ActionLink以这种形式生成链接：

/动作/型号/ ID /参数1 /参数2

我用过： <%= Html.ActionLink("Link Text", "Action", "Model", new { id = var, parament1=var1 }, null) %>但它总是看起来像/ Action /型号/编号？参数1 =可变

我在Stackoverflow和其他地方看到了类似的问题，但我找不到一个有效/有意义的解决方案。任何帮助，将不胜感激。

@John：我注册了以下路线： routes.MapRoute("Alternate","{controller}/{action}/{id}/{Heading}", new { controller = "Designation", action = "Details", id = "", Heading = "" }

然后我在我的视图中有以下代码： <%= Html.ActionLink("Link Text", "Action", "Model", new { Id = model.Id, Heading = model.Heading }, null) %>

我得到/ Model / Action / Id？标题= var1我希望它为/ Model / Action / Id / var1

解答：我在global.asax.cs文件中添加了以下路由，并正确生成了链接。 routes.MapRoute（“Something”，“MyModel / MyAction / {Id} / {Heading}”，new {controller =“MyModel”，action =“MyAction”，id =“”，heading =“”}，new {controller = @“[^。] *”}）;

I'm trying to use Html.ActionLink to generate a link with in this form:

/Action/Model/Id/Parameter1/Parameter2

I've used: <%= Html.ActionLink("Link Text", "Action", "Model", new { id = var, parament1=var1 }, null) %> but it always ends up looking like /Action/Model/Id?parameter1=variable

I've seen similar questions on Stackoverflow and elsewhere, but I can't find a solution that works/makes sense. Any help would be appreciated.

@John: I have the following route registered: routes.MapRoute("Alternate","{controller}/{action}/{id}/{Heading}", new { controller = "Designation", action = "Details", id = "", Heading = "" }

I then have the following code in my view: <%= Html.ActionLink("Link Text", "Action", "Model", new { Id = model.Id, Heading = model.Heading }, null) %>

I get /Model/Action/Id?Heading=var1 I want it as /Model/Action/Id/var1

ANSWER: I added the following route to my global.asax.cs file and the links generated correctly. routes.MapRoute("Something", "MyModel/MyAction/{Id}/{Heading}", new { controller = "MyModel", action = "MyAction", id = "", heading = "" }, new { controller = @"[^.]*" });