如何根据js中的命名空间和有趣名称调用django视图函数？(How to call a django view function based on its namespace and fun nam

如何根据js中的命名空间和有趣名称调用django视图函数？(How to call a django view function based on its namespace and fun name from js?)

要从HTML调用Django视图，我们使用以下内容：

"{% url 'namespace: view_fun' %}"

但是如何从Javascript中做到这一点？

谢谢！

To call a Django view from HTML we use the following:

"{% url 'namespace: view_fun' %}"

But how to do this from Javascript?

Thank you!

最满意答案

一种hacky方法是在模板中包含以下脚本来引用javascript文件。

<script> var fun_url = "{% url 'namespace: view_fun' %}"; </script>

然后在引用的javascript文件中期待这个fun_url变量。

One hacky way to do it would be to include following script in your template that references the javascript file.

<script> var fun_url = "{% url 'namespace: view_fun' %}"; </script>

And then expecting this fun_url variable in your referenced javascript file.