如何在OrderedDicts中的键相同时添加两个OrderedDict？(How to add two OrderedDict when key is same in both the Ordere

如何在OrderedDicts中的键相同时添加两个OrderedDict？(How to add two OrderedDict when key is same in both the OrderedDicts?)

我的第一个订购的迪克是

OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})])

我的第二个命令是

OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})])

在上面的两个ord​​eredDict中，键是相同的，但值不同。 如何合并来自这两个ord​​eredDicts的相同键的值并创建一个新的？

My first orderedDic is

OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})])

My second orderedDict is

OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})])

In the above two orderedDict, keys are same but values are different. How to merge the values of the same keys from both the orderedDicts and make one new?

最满意答案

这是它的代码：

from collections import OrderedDict a= OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})]) b=OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})]) c=OrderedDict() for key in a: temp=b[key] temp.update(a[key]) c[key]=temp print c

你的新词典存储在c中。 记住.update()更新字典本身并返回None 。

Here is the code to it:

from collections import OrderedDict a= OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})]) b=OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})]) c=OrderedDict() for key in a: temp=b[key] temp.update(a[key]) c[key]=temp print c

Your new dictionary is stored in c. Remember .update() updates the dictionary itself and returns None.