如何在OrderedDicts中的键相同时添加两个OrderedDict?(How to add two OrderedDict when key is same in both the OrderedDicts?)
我的第一个订购的迪克是
OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})])我的第二个命令是
OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})])在上面的两个orderedDict中,键是相同的,但值不同。 如何合并来自这两个orderedDicts的相同键的值并创建一个新的?
My first orderedDic is
OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})])My second orderedDict is
OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})])In the above two orderedDict, keys are same but values are different. How to merge the values of the same keys from both the orderedDicts and make one new?
最满意答案
这是它的代码:
from collections import OrderedDict a= OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})]) b=OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})]) c=OrderedDict() for key in a: temp=b[key] temp.update(a[key]) c[key]=temp print c你的新词典存储在c中。 记住.update()更新字典本身并返回None 。
Here is the code to it:
from collections import OrderedDict a= OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'value': 0.5, 'valueSat': 50000000, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'value': 0.01349045, 'valueSat': 1349045, 'txid': '4c4e1609392f6744cdf9ff57614eb5f6905f39baba8f046c3b3bd5a1e6b573c8'})]) b=OrderedDict([('3LEmxb4G9q5XnP9H5653ncMAbAgbDCzz8U', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 3}), ('1ErSPkXKfdVgjseia1psccr6ng4zbyLNSE', {'account_id': None, 'last_block': '', 'n_conf': 0, 'total_confirmations': 6})]) c=OrderedDict() for key in a: temp=b[key] temp.update(a[key]) c[key]=temp print cYour new dictionary is stored in c. Remember .update() updates the dictionary itself and returns None.
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