检测特定的iPhone / iPod touch型号

本文介绍了检测特定的iPhone / iPod touch型号的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

可能重复： 使用iPhone SDK确定设备（iPhone，iPod Touch）

我正在制作一款利用iPhone的对等蓝牙功能的游戏（可能还有iPod touch第二代）。但是，要阻止用户尝试在iPod 1st和iPhone 2G上播放多人游戏，我需要检查特定的设备型号。

I am making a game that utilizes the peer-to-peer bluetooth capabilities of the iPhone (and probably the iPod touch 2nd generation). However, to stop the users from trying to play a multiplayer on an iPod 1st gen and iPhone 2G I need to check for the specific device model.

[[UIDevice currentDevice] model]只会告诉我该设备是iPhone还是iPod touch。有没有办法检查特定的设备型号，如：iPhone 3GS，iPod touch 1st generation或其他什么。

[[UIDevice currentDevice] model] will only tell me if the device is an "iPhone" or an "iPod touch". Is there a way to check for the specific device model, like: "iPhone 3GS", "iPod touch 1st generation" or something.

编辑：

UIDevice有一个类别（我认为它是由Erica Sadun创建的，我不赞成它），它使用以下代码来获取具体信息设备模型。您可以在此处找到整个类别以及其他有用的内容： github/erica/uidevice -extension

There is a category to UIDevice (I think it's created by Erica Sadun, I don't take credit for it) that uses the following code to get the specific device model. You can find the whole category here along with other useful stuff: github/erica/uidevice-extension

#include <sys/types.h> #include <sys/sysctl.h> @implementation UIDevice (Hardware) /* Platforms iPhone1,1 -> iPhone 1G iPhone1,2 -> iPhone 3G iPod1,1 -> iPod touch 1G iPod2,1 -> iPod touch 2G */ - (NSString *) platform { size_t size; sysctlbyname("hw.machine", NULL, &size, NULL, 0); char *machine = malloc(size); sysctlbyname("hw.machine", machine, &size, NULL, 0); NSString *platform = [NSString stringWithCString:machine encoding:NSUTF8StringEncoding]; free(machine); return platform; }

此作品和使用此功能的应用程序最近已在AppStore中获得批准。

This works and apps using this have been lately approved in the AppStore.

推荐答案

最完整的UIDevice（硬件）类别可能是 github/erica/uidevice-extension/ （作者Erica Sadun）：

Most complete UIDevice (Hardware) category probably is github/erica/uidevice-extension/ (by Erica Sadun):

[[UIDevice currentDevice] platformType] // ex: UIDevice4GiPhone [[UIDevice currentDevice] platformString] // ex: @"iPhone 4G"