我有以下形式的JSON数组:
I have a JSON array of the form:
[ [ 1232324343, "A", "B", 3333, "E" ], [ 12345424343, "N", "M", 3133, "R" ] ]我想使用Jackson库将父数组的每个元素映射到POJO.我试过了:
I want to map each element of the parent array to a POJO using the Jackson library. I tried this:
ABC abc = new ABC(); ObjectMapper mapper = new ObjectMapper(); JsonNode jsonNode = mapper.readTree(data).get("results"); if (jsonNode.isArray()) { for (JsonNode node : jsonNode) { String nodeContent = mapper.writeValueAsString(node); abc = mapper.readValue(nodeContent,ABC.class); System.out.println("Data: " + abc.getA()); } }其中ABC是我的POJO类,而abc是对象,但是出现以下异常:
where ABC is my POJO class and abc is the object but I get the following exception:
com.fasterxml.jackson.databind.JsonMappingException:无法反序列化com.demo.json.model.ABC实例
com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of com.demo.json.model.ABC
我的POJO看起来像这样:
My POJO looks like this:
class ABC{ long time; String a; String b; int status; String c; }有人可以提出解决方案吗?
Can someone suggest a solution for this?
在StackOverflow和其他论坛上咨询了很多答案之后,我遇到了一个解决方案.我将readValue()方法的返回值映射到一个POJO对象数组中.
EDIT 2: After consulting a lot of answers on StackOverflow and other forums, I came across one solution. I mapped the returned value of readValue() method into an array of POJO objects.
ABC[] abc = mapper.readValue(nodeContent, ABC[].class);但是现在我得到了一个单独的例外
But now I am getting a separate exception
无法构造ABC实例:没有长/长参数构造函数/工厂方法可从Number值反序列化(1552572583232)
Can not construct instance of ABC: no long/Long-argument constructor/factory method to deserialize from Number value (1552572583232)
我尝试了以下方法,但没有任何效果: 1.强制Jackson使用
I have tried the following but nothing worked: 1. Forcing Jackson to use ints for long values using
mapper.configure(DeserializationFeature.USE_LONG_FOR_INTS, true);2.在POJO中使用包装器类Long代替long
2. Using wrapper class Long instead of long in the POJO
有人可以帮我吗?
推荐答案您可以为该对象使用ARRAY形状.您可以使用JsonFormat注释:
You can use ARRAY shape for this object. You can do that using JsonFormat annotation:
@JsonFormat(shape = Shape.ARRAY) class ABC {并将其反序列化:
ABC[] abcs = mapper.readValue(json, ABC[].class);有问题的更改后进行编辑.
您的示例代码可能如下所示:
EDIT after changes in question.
You example code could look like this:
JsonNode jsonNode = mapper.readTree(json); if (jsonNode.isArray()) { for (JsonNode node : jsonNode) { String nodeContent = mapper.writeValueAsString(node); ABC abc = mapper.readValue(nodeContent, ABC.class); System.out.println("Data: " + abc.getA()); } }我们可以使用convertValue方法并跳过序列化过程:
We can use convertValue method and skip serializing process:
JsonNode jsonNode = mapper.readTree(json); if (jsonNode.isArray()) { for (JsonNode node : jsonNode) { ABC abc = mapper.convertValue(node, ABC.class); System.out.println("Data: " + abc.getA()); } }甚至:
JsonNode jsonNode = mapper.readTree(json); ABC[] abc = mapper.convertValue(jsonNode, ABC[].class); System.out.println(Arrays.toString(abc));更多推荐
使用Jackson将Json Array映射到POJO
发布评论