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问题描述
我有一个code座:
int main () { char *p1 = "Hello"; char *p2; p2 = (char*)malloc (20); memset (p2, 0, 20); while (*p2++ = *p1++); printf ("%s\n", p2); }但我无法解释该行的工作而(* P2 ++ = * P1 ++);你可以让我知道这个操作公式中的顺序?
But I can not explain the working of the line while (*p2++ = *p1++); Could you let me know the order of operation in this formula?
推荐答案这是经典的C code试图把一切在一行看起来非常聪明。
It's classic C code trying to look extremely clever by putting everything in one line.
而(* P2 ++ = * P1 ++); 等同于
strcpy(p2, p1); p1 += strlen(p1) + 1; p2 += strlen(p2) + 1;在换句话说,它拷贝一个空值终止字符串, P1 结束了指向源字符串的结束和 P2 指向目标字符串的结尾。
In other words, it copies a null-terminated string, with p1 ending up pointing to the end of the source string and p2 pointing to the end of the destination string.
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这是什么,而(* P2 ++ = * P1 ++);意思?
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