Typecast UnsafeMutablePointer 为UnsafeMutablePointer (Typecast UnsafeMutablePointer to UnsafeMutableP

Typecast UnsafeMutablePointer 为UnsafeMutablePointer <#Struct type＃>(Typecast UnsafeMutablePointer to UnsafeMutablePointer<#Struct type#>)

我在Swift中创建了一个名为RGB的结构，很简单：

struct PixelRGB { var r: CUnsignedChar = 0 var g: CUnsignedChar = 0 var b: CUnsignedChar = 0 init(red: CUnsignedChar, green: CUnsignedChar, blue: CUnsignedChar) { r = red g = green b = blue } }

我有一个指针var imageData: UnsafeMutablePointer<PixelRGB>! 。

我希望给这个指针malloc一些空间，但是malloc返回UnsafeMutablePointer<Void> ，我不能像下面这样UnsafeMutablePointer<Void>它：

imageData = malloc(UInt(dataLength)) as UnsafeMutablePointer<PixelRGB> // 'Void' is not identical to `PixelRGB`

无论如何解决这个问题？ 感谢您的帮助！

I created a struct in Swift called RGB, simple enough:

struct PixelRGB { var r: CUnsignedChar = 0 var g: CUnsignedChar = 0 var b: CUnsignedChar = 0 init(red: CUnsignedChar, green: CUnsignedChar, blue: CUnsignedChar) { r = red g = green b = blue } }

And I have a pointer var imageData: UnsafeMutablePointer<PixelRGB>!.

I wish to malloc some space for this pointer, but malloc returns UnsafeMutablePointer<Void> and I cannot cast it like below:

imageData = malloc(UInt(dataLength)) as UnsafeMutablePointer<PixelRGB> // 'Void' is not identical to `PixelRGB`

Anyway to solve this? Thank you for your help!

最满意答案

我想你想说的是这样的：

imageData = UnsafeMutablePointer<PixelRGB>.alloc(dataLength)

I think what you want to say is something like this:

imageData = UnsafeMutablePointer<PixelRGB>.alloc(dataLength)