函数可以作为参数传递吗?

编程入门行业动态更新时间:2024-10-23 21:38:18

本文介绍了函数可以作为参数传递吗?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

在Java中，我可以做类似

In Java I can do something like

derp(new Runnable { public void run () { /* run this sometime later */ } })

并在以后的方法中运行"代码.处理(匿名内部类)很痛苦，但是可以做到.

and "run" the code in the method later. It's a pain to handle (anonymous inner class), but it can be done.

Go有什么可以促进函数/回调作为参数传递的东西吗?

Does Go have something that can facilitate a function/callback being passed in as a parameter?

推荐答案

是的，请考虑以下示例:

Yes, consider some of these examples:

package main import "fmt" // convert types take an int and return a string value. type convert func(int) string // value implements convert, returning x as string. func value(x int) string { return fmt.Sprintf("%v", x) } // quote123 passes 123 to convert func and returns quoted string. func quote123(fn convert) string { return fmt.Sprintf("%q", fn(123)) } func main() { var result string result = value(123) fmt.Println(result) // Output: 123 result = quote123(value) fmt.Println(result) // Output: "123" result = quote123(func(x int) string { return fmt.Sprintf("%b", x) }) fmt.Println(result) // Output: "1111011" foo := func(x int) string { return "foo" } result = quote123(foo) fmt.Println(result) // Output: "foo" _ = convert(foo) // confirm foo satisfies convert at runtime // fails due to argument type // _ = convert(func(x float64) string { return "" }) }