本文介绍了如何在edittext上验证IP以完成此操作?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
public void checkIP(String Value) { Pattern pattern = Patternpile("[0-255].[0-255].[0-255].[0-255]"); Matcher matcher = pattern.matcher(Value); boolean IPcheck = matcher.matches(); if(IPcheck){ boolean IsValidData=true; String _strServer=((EditText)findViewById(R.id.txtserver)).getText().toString().trim(); } //it is IP else{ Toast.makeText(getBaseContext(), "Please Check Your IP Format: ", Toast.LENGTH_SHORT).show(); } //it is not IP } public void loginbuttonclick(View v) { ProgressDialog pDialog = new ProgressDialog(LoginActivity.this); // Set progressbar title pDialog.setTitle("Authentication"); // Set progressbar message pDialog.setMessage("Authenticating..."); pDialog.setIndeterminate(false); pDialog.setCancelable(false); // Show progressbar pDialog.show(); try { //Validate input data boolean IsValidData=true; String _strServer=((EditText)findViewById(R.id.txtserver)).getText().toString().trim();; //"192.168.0.172"; String _strUser=((EditText)findViewById(R.id.txtuser)).getText().toString().trim();;//"admin"; String _strPass=((EditText)findViewById(R.id.txtpass)).getText().toString();//"admin"; if(_strServer==null || _strServer.isEmpty() || _strServer=="") { IsValidData=false; pDialog.dismiss(); Toast.makeText(getBaseContext(),"Kindly enter valid server ip! : ",Toast.LENGTH_SHORT).show(); }
我尝试过: 对于null和Empty我已经完成了,所以如何放置checkIP?请帮助..
What I have tried: For null and Empty I have done, so How do I put checkIP? please help..
推荐答案我想说使用这个正则表达式来确保它的格式正确 ([0-9] {1,3} \。){3} [0-9] {1,3} 然后 将它拆分为'。',解析为一个整数并检查它是否在范围(0-255)或不在 I would say use this regular expression to make sure it's in the proper format ([0-9]{1,3}\.){3}[0-9]{1,3} and then split it on '.', parse it to an integer and check to see whether it lies in range (0-255) or not
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如何在edittext上验证IP以完成此操作?
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