文本文件中的唯一字[重复](Unique words in a text file [duplicate])

文本文件中的唯一字[重复](Unique words in a text file [duplicate])

这个问题在这里已经有了答案：

解析文本文件中的独特单词 2个答案

我想知道是否有方法在文本文件中查找（并显示）所有唯一的单词（出现一次的单词）？ 这可以通过使用命令行来完成吗？ 或者我会不得不使用类似python脚本的东西？

This question already has an answer here:

Parsing unique words from a text file 2 answers

I was wondering if there is a way to find (and display) all the unique words (words that appear once) in a text file? Could this be done just using the command line? Or would I have to use something like a python script?

最满意答案

如果你不想编写应用程序，那么我可以想到的最简单的方法就是使用powershell。 看到这个：

https://msdn.microsoft.com/en-us/powershell/reference/5.1/microsoft.powershell.utility/get-unique

Microsoft提供的示例使用唯一字词列表填充变量：

$A = $(foreach ($line in Get-Content C:\Test1\File1.txt) {$line.tolower().split(" ")}) | sort | Get-Unique

您可能希望使用额外的分隔符来分隔标点符号，例如：

$A = $(foreach ($line in Get-Content C:\test.txt) {$line.tolower().split(" .,?!;:")}) | sort | Get-Unique

把它放在一个扩展名为.ps1的文件中，你可以从命令行运行它。 为了从变量中获取数值，只需在变量的第二行将结果回显给屏幕：

$A

要获得数组中项目的数量，您可以这样做：

$A.count

If you don't want to write an application then the easiest way that I can think to accomplish this is to use powershell. See this:

https://msdn.microsoft.com/en-us/powershell/reference/5.1/microsoft.powershell.utility/get-unique

The example that Microsoft provides populates a variable with the list of unique words:

$A = $(foreach ($line in Get-Content C:\Test1\File1.txt) {$line.tolower().split(" ")}) | sort | Get-Unique

You may wish you use additional delimiters though to split on punctuation such as this:

$A = $(foreach ($line in Get-Content C:\test.txt) {$line.tolower().split(" .,?!;:")}) | sort | Get-Unique

Place this in a file with the extension .ps1 and you can run it from the command line. In order to get the values out of the variable just a second line with the variable to echo the result to the screen:

$A

To get the count of items in the array you could do this:

$A.count