使用扩展运算符设置键名(Set keyname with spread operator)

使用扩展运算符设置键名(Set keyname with spread operator)

是否可以动态设置关键名称来传播运算符？

例如，我有：

'first, second, third'.split(','); // Array(3) : [ 'first', 'second', 'third' ]

我想有一个这样的对象

{ 'first': 'first', 'second': 'second', 'third': 'third' }

通过这样做，我现在得到：

{ ...'first, second, third'.split(',') }; // { 1: 'first', 2: 'second', 3: 'third' }

我可以动态设置它，或者我必须迭代并在此时手动执行它？

我已经结合使用这两个答案：

const toObject = str => Object.assign(...str.split(/\s*,\s*/).map(key => ({ [key]: key })));

Is it possible to dynamically set key name to spread operator?

For example I have:

'first, second, third'.split(','); // Array(3) : [ 'first', 'second', 'third' ]

I want to have an object like this

{ 'first': 'first', 'second': 'second', 'third': 'third' }

By doing this right now I get:

{ ...'first, second, third'.split(',') }; // { 1: 'first', 2: 'second', 3: 'third' }

Can I dynamically set it or I have to iterate through and do it manually at this point?

I've ended up combine the two answers to use this:

const toObject = str => Object.assign(...str.split(/\s*,\s*/).map(key => ({ [key]: key })));

最满意答案

乔纳斯的解决方案很聪明。 我喜欢。 这是一个替代方案：

function toObject(str) {
  const parts = str.split(/\s*,\s*/);
  return parts.reduce((obj, part) => {
    obj[part] = part;
    return obj;
  }, {});
}

console.log(toObject('first, second, third')); 
  
 
 
 请注意，我使用split(/\s*,\s*/)而不是split(',')来消除部件之间的空白。 
 
 如果你遇到这种情况，这可以简化为以下一行： 
 
 
 
  
  
const toObject = str =>
  str.split(/\s*,\s*/).reduce((o, p) => (o[p] = p, o), {});

console.log(toObject('first, second, third')); 
  
 
Jonas' solution is clever. I like it. Here's an alternative:
 
 
 
  
  
function toObject(str) {
  const parts = str.split(/\s*,\s*/);
  return parts.reduce((obj, part) => {
    obj[part] = part;
    return obj;
  }, {});
}

console.log(toObject('first, second, third')); 
  
 
 
Note that I use split(/\s*,\s*/) instead of split(',') to eliminate whitespace between parts.
 
This can be reduced to the following one-liner, if you're into that sort of thing:
 
 
 
  
  
const toObject = str =>
  str.split(/\s*,\s*/).reduce((o, p) => (o[p] = p, o), {});

console.log(toObject('first, second, third'));