通过不同类型的指针删除缓冲区？

本文介绍了通过不同类型的指针删除缓冲区？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

说我有以下C ++：

char *p = new char[cb]; SOME_STRUCT *pSS = (SOME_STRUCT *) p; delete pSS;

根据C ++标准，这是否安全？是否需要转回 char * ，然后使用 delete [] ？我知道它将工作在大多数C ++编译器，因为它是普通的普通数据，没有析构函数。确保安全吗？

Is this safe according to the C++ standard? Do I need to cast back to a char* and then use delete[]? I know it'll work in most C++ compilers, because it's plain-ordinary-data, with no destructors. Is it guaranteed to be safe?

推荐答案

不能保证安全。这里有一个相关的链接在C + + FAQ lite：

It's not guaranteed to be safe. Here's a relevant link in the C++ FAQ lite:

[16.13]删除数组时可以删除 [] 的某些内置类型（ char ， int 等）？

[16.13] Can I drop the [] when deleting array of some built-in type (char, int, etc.)?

www.parashift/c++-faq -lite / freestore-mgmt.html＃faq-16.13