在php中获取foreach循环中的特定记录(Fetch specific record in foreach loop in php)
我想在foreach循环中获取两个记录。
获取记录后,接下来的两个记录为分页
$post_img_id=array(21,24,25,28,40,44,46,47,52,78,88,89,92,101); //this is id of table data $total=count($post_img_id,COUNT_RECURSIVE); //total record $item=2; $total_page=ceil($total/$item); $cur_page=isset($_GET['page'])?$_GET['page']:1; $k=($cur_page-1)*$item; foreach($post_img_id as $id) { if($co<=10){ $post_img_q="select * from $post where id=$id LIMIT $k,$item"; $post_img_res=mysql_query($post_img_q) or die(mysql_error()); while($post_img_row=mysql_fetch_assoc($post_img_res)) { echo 'record'; } } ?>如何解决这个问题呢 ? 请帮帮我 !
提前谢谢!
I want to fetch two record in foreach loop.
After fetch record, next two record for pagination
$post_img_id=array(21,24,25,28,40,44,46,47,52,78,88,89,92,101); //this is id of table data $total=count($post_img_id,COUNT_RECURSIVE); //total record $item=2; $total_page=ceil($total/$item); $cur_page=isset($_GET['page'])?$_GET['page']:1; $k=($cur_page-1)*$item; foreach($post_img_id as $id) { if($co<=10){ $post_img_q="select * from $post where id=$id LIMIT $k,$item"; $post_img_res=mysql_query($post_img_q) or die(mysql_error()); while($post_img_row=mysql_fetch_assoc($post_img_res)) { echo 'record'; } } ?>how to solve this problem ? please help me !
Thanx for Advance !
最满意答案
请使用array_chunk()参考此链接: http ://php.net/manual/en/function.array-chunk.php
即: print_r(array_chunk($post_img_id, 2, true));
$nameofArray = array_chunk($post_img_id, 2, true); foreach($nameofArray as $Array) { //your code here... }在你的代码中检查这个,它将你的数组分成2个部分,你将获得2个记录的数组,这样它将更容易帮助你分页记录。
please use array_chunk() refer this link :http://php.net/manual/en/function.array-chunk.php
i.e : print_r(array_chunk($post_img_id, 2, true));
$nameofArray = array_chunk($post_img_id, 2, true); foreach($nameofArray as $Array) { //your code here... }check this in your code its devide your array in portion of 2 where you will get array of 2 records so it will help you more easily to paginate record.
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