如何从 Swift 中的 UIColor 获取 RGB 代码 (INT)

本文介绍了如何从 Swift 中的 UIColor 获取 RGB 代码 (INT)的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想在 Swift 中获取 UIColor 的 RGB 值:

I would like to get the RGB Value of an UIColor in Swift:

let swiftColor = UIColor(red: 1, green: 165/255, blue: 0, alpha: 1) println("RGB Value is:"); println(swiftColor.getRGB()); <<<<<< How to do that ?

在 Java 中，我会这样做:

In Java I would do it as follows:

Color cnew = new Color(); int iColor = cnew.rgb(1, 165/255, 0); System.out.println(iColor);

我应该如何获得这个值?

How should I get this value?

推荐答案

Java getRGB()返回一个整数，表示默认 sRGB 颜色空间中的颜色(位 24-31 是 alpha，16-23 是红色，8-15 是绿色，0-7 是蓝色).

The Java getRGB() returns an integer representing the color in the default sRGB color space (bits 24-31 are alpha, 16-23 are red, 8-15 are green, 0-7 are blue).

UIColor 没有这样的方法，但是你可以自己定义:

UIColor does not have such a method, but you can define your own:

extension UIColor { func rgb() -> Int? { var fRed : CGFloat = 0 var fGreen : CGFloat = 0 var fBlue : CGFloat = 0 var fAlpha: CGFloat = 0 if self.getRed(&fRed, green: &fGreen, blue: &fBlue, alpha: &fAlpha) { let iRed = Int(fRed * 255.0) let iGreen = Int(fGreen * 255.0) let iBlue = Int(fBlue * 255.0) let iAlpha = Int(fAlpha * 255.0) // (Bits 24-31 are alpha, 16-23 are red, 8-15 are green, 0-7 are blue). let rgb = (iAlpha << 24) + (iRed << 16) + (iGreen << 8) + iBlue return rgb } else { // Could not extract RGBA components: return nil } } }

用法:

let swiftColor = UIColor(red: 1, green: 165/255, blue: 0, alpha: 1) if let rgb = swiftColor.rgb() { print(rgb) } else { print("conversion failed") }

请注意，这仅在 UIColor 已在RGB 兼容"色彩空间(例如 RGB、HSB 或 GrayScale).它可能如果颜色是从 CIColor 或图案创建的，则失败图像，在这种情况下 nil 被返回.

Note that this will only work if the UIColor has been defined in an "RGB-compatible" colorspace (such as RGB, HSB or GrayScale). It may fail if the color has been created from an CIColor or a pattern image, in that case nil is returned.

备注: 正如@vonox7 所注意到的，返回值可能是负数在 32 位平台上(Java getRGB() 方法也是如此).如果不需要，请将 Int 替换为 UInt 或 Int64.

Remark: As @vonox7 noticed, the returned value can be negative on 32-bit platforms (which is also the case with the Java getRGB() method). If that is not wanted, replace Int by UInt or Int64.

反向转换是

extension UIColor { convenience init(rgb: Int) { let iBlue = rgb & 0xFF let iGreen = (rgb >> 8) & 0xFF let iRed = (rgb >> 16) & 0xFF let iAlpha = (rgb >> 24) & 0xFF self.init(red: CGFloat(iRed)/255, green: CGFloat(iGreen)/255, blue: CGFloat(iBlue)/255, alpha: CGFloat(iAlpha)/255) } }