如何在构造函数中初始化 char 数组?

本文介绍了如何在构造函数中初始化 char 数组?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我在声明和初始化 char 数组时遇到问题.它总是显示随机字符.我创建了一小段代码来展示我在更大的程序中尝试的内容:

I'm having trouble declaring and initializing a char array. It always displays random characters. I created a smaller bit of code to show what I'm trying in my larger program:

class test { private: char name[40]; int x; public: test(); void display() { std::cout<<name<<std::endl; std::cin>>x; } }; test::test() { char name [] = "Standard"; } int main() { test *test1 = new test; test1->display(); }

很抱歉，如果我的格式不好，我几乎无法弄清楚这个网站，更不用说如何修复我的代码了 :(

And sorry if my formatting is bad, I can barely figure out this website let alone how to fix my code :(

推荐答案

如果没有特殊原因不使用std::string，请使用std::string.

If there are no particular reasons to not use std::string, do use std::string.

但是如果你真的需要初始化那个字符数组成员，那么:

But if you really need to initialize that character array member, then:

#include <assert.h> #include <iostream> #include <string.h> using namespace std; class test { private: char name[40]; int x; public: test(); void display() const { std::cout<<name<<std::endl; } }; test::test() { static char const nameData[] = "Standard"; assert( strlen( nameData ) < sizeof( name ) ); strcpy( name, nameData ); } int main() { test().display(); }