在Python 3和括号中定义函数(Defining functions in Python 3 and Parenthesis)

在Python 3和括号中定义函数(Defining functions in Python 3 and Parenthesis)

我有这个教程这样做

c = (x, y) def addVectors((angle1, length1), (angle2, length2)): do something return

然后用以下方式调用addVectors ：

addVector((a, b), c)

但python 3只是给了我一个括号上的语法错误(angle1, lenght1)

谢谢

I have this tutorial that does this

c = (x, y) def addVectors((angle1, length1), (angle2, length2)): do something return

and then calls addVectors with:

addVector((a, b), c)

but python 3 just gives me a syntax error on the parenthesis around (angle1, lenght1)

Thanks

最满意答案

这在Python 2中是可行的，但是在Python 3中通过PEP-3113删除

解决方法是在函数内解压参数：

def addVectors(angle1_length1, angle2_length2): angle_1, length1 = angle1_length1 angle_2, length2 = angle2_length2 do something return

This used to be possible in Python 2, but was removed in Python 3 via PEP-3113

The solution is to unpack the argument inside the function:

def addVectors(angle1_length1, angle2_length2): angle_1, length1 = angle1_length1 angle_2, length2 = angle2_length2 do something return