C ++ STL向量迭代器不兼容

本文介绍了C ++ STL向量迭代器不兼容的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 // Erase the missing items vector<AlignedFDRData>::size_type StandardNum = FDRFreq.at(0).fData.size(); vector<AlignedFDRData>::iterator iter = FDRFreq.begin(); while (iter != FDRFreq.end()){ if( iter->fData.size() < StandardNum){ FDRFreq.erase(iter); } else{ ++iter; } }

此部分用于擦除FDRFreq矢量项，其中数据长度小于标准数，但调试断言失败：向量迭代器不兼容。

This part is used to erase the FDRFreq vector item, in which the data length is smaller than the standard number, but the debug assertion failed: vector iterators incompatible. I am a green hand in C++ STL, thanks for your kindly help.

推荐答案

您的代码需要成为

while (iter != FDRFreq.end()){ if( iter->fData.size() < StandardNum){ iter = FDRFreq.erase(iter); } else{ ++iter; } }

向量迭代器不兼容重新使用已被无效 - 也就是说，不能保证它指向的元素仍然存在于该存储器位置。向量元素的擦除使该位置之后的迭代器无效。 .erase 返回一个新的，有效的迭代器，您可以改用。

"vector iterators incompatible" means that the iterator you're using has been invalidated - that is to say, there is no guarantee that the elements it points to still exist at that memory location. An erase of a vector element invalidates the iterators following that location. .erase returns a new, valid iterator you can use instead.

如果你刚接触STL，强烈建议您阅读Scott Myer的有效STL （以及 Effective C ++ ）

If you're new to STL, I highly recommend you read Scott Myer's Effective STL (and Effective C++, while you're at it)