本文介绍了将指针的二维数组传递给函数 C的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个二维指针数组
main.c Int32 * pRxSeqAddr[2][2]; func(pRxSeqAddr);/
func.c void func( Int32** pRxSeqAddrPtr) { /// }我收到此错误:
argument of type "Int32 *(*)[2]" is incompatible with parameter of type "Int32 **我知道如果它是一维指针数组,那么这个函数调用很好,但二维却让我烦恼..
I know if it was 1D array of pointer then this function call is fine, but 2D is nagging me..
请帮忙
推荐答案将 func.c 更改为:
Change func.c to:
void func(Int32 *pRxSeqAddrPtr[][2]) { }一般来说,要将二维数组传递给函数,您需要为除第一维之外的所有维度指定数组维度,因此在此示例中,最后一维需要 [2],但您可以选择将其省略为第一维,即
In general, to pass 2D arrays to functions you need to specify the array dimensions for all but the first dimension, so in this example you need the [2] for the last dimension but you can optionally omit it for the first dimension, i.e.
void func(Int32 *pRxSeqAddrPtr[2][2]) { }也是有效的,但有点多余.
would also be valid, but somewhat redundant.
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将指针的二维数组传递给函数 C
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