以类型安全的方式将指针转换为指针

本文介绍了以类型安全的方式将指针转换为指针的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

给出以下代码:

class Base { public: virtual ~Base() = default; }; class Derived : public Base { }; int main(void) { Derived d; Base* pb = &d; Base** ppb = &pb; Derived** ppd = ...; // Can this be defined in a type-safe manner? return 0; }

是否可以为分配给ppd的类型提供安全的表达式，而无需引入类型为Derived*的中间变量?

Is it possible to give a type-safe expression for the assignment to ppd, without introducing an intermediary variable of type Derived*?

推荐答案

AFAIK，并非没有声明指向d的Derived指针.指向d(pb)的Base指针已经通过抽象丢失了类型信息，没有不安全的强制转换就无法恢复.

AFAIK, not without declaring a Derived pointer to d. The Base pointer to d (pb) has already lost type information through abstraction, which cannot be recovered without a unsafe cast.

由于要声明指向Derived的指针，因此首先需要一个指向Derived的指针.例如:

Since you're declaring a pointer to a pointer to a Derived, you need a pointer to a Derived first. Eg:

Derived* pd = &d; Derived** ppd = &pd;

这两个定义都是类型安全的，在编译时检查.

Both of those definitions are type-safe, checked at compile time.