如何创建指向成员函数的函数指针?

本文介绍了如何创建指向成员函数的函数指针?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

代码:

struct A { void* f(void *) { } }; int main() { void * (*fp)(void *); fp = &A::f; }

编译:

|12|error: cannot convert 'void* (A::*)(void*)' to 'void* (*)(void*)' in assignment|

我尝试了很多方法，但是都失败了……该怎么做?

I have tried many ways, but all failed... How to do that?

推荐答案

对于常规成员指针，您需要声明其属于指针类型的成员的类型；

For a regular member pointer, you'll need to declare the type it's a member of on the pointer type;

int main() { void * (A::*fp)(void *); fp = &A::f; }