参考成员函数？

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我最近发现在C ++中有一个引用到函数的概念:)。 所以有指针到函数和指针到成员函数不同的类型。问题出现了。是否有引用到成员函数的概念？

我试图编译以下代码，但GCC 3.4.6给出错误。

#include< iostream> using namespace std; class A { public： virtual void Af（）const { cout< A :: Af（）< endl } }; int main（）{ typedef void（A ::& MemFnc）（）const; MemFnc mf =& A :: Af; A a; （a。* mf）（）; return 0; }

解决方案

（（§8.3.3）中的 3 - 2003），

指向成员的指针不能指向类的静态成员（9.4）类型或cv void。[注：另见5.3和5.5。类型指向成员的指针与类型指针不同，即，指向成员的指针仅由指向成员声明符语法的指针声明，并且从不由指针声明符语法声明。 在C ++中没有引用到成员类型。

I recently find out that there is a reference-to-function concept in C++ :). So as there are pointer-to-function and pointer-to-member-function different types. The question arises. Is there a "reference-to-member-function" concept?

I tried to compile the following code, but GCC 3.4.6 gives an error.

#include <iostream> using namespace std; class A { public: virtual void Af() const { cout << "A::Af()" << endl; } }; int main() { typedef void (A::& MemFnc)() const; MemFnc mf = &A::Af; A a; (a.*mf)(); return 0; }

解决方案

There is no such a thing called reference to member in C++.

The language specification explicitly says in a note (§8.3.3/3 - 2003) that,

A pointer to member shall not point to a static member of a class (9.4), a member with reference type, or "cv void." [Note: see also 5.3 and 5.5. The type "pointer to member" is distinct from the type "pointer", that is, a pointer to member is declared only by the pointer to member declarator syntax, and never by the pointer declarator syntax. There is no "reference-to-member" type in C++.