我正在尝试使用malloc分配两个不同的4096字节,并使用不同的值初始化这些分配.之后,我希望其中一个指针指向另一个分配,不带"更改p1的值,不带"复制数据.我想将第二个分配重新映射"到第一个分配,这基本上应该更改进程页面表中的虚拟地址,即不涉及复制.当我运行此代码时,我得到mremap失败.任何想法如何做到这一点?
I am trying to allocate two different 4096 bytes using malloc and initialize these allocations with different values. Afterwards, I want one of the pointers to point to the other allocation "without" changing the value of p1 and "without" copying the data. I want to "remap" the second allocation to the first allocation which should basically change the virtual address in the page table of the process, i.e. no copying is involved. When I run this code, I get that mremap failed. Any idea how to accomplish this?
int main(){ char *p1 = (char *)malloc(4096); memset(p1, 'a', 4096); char *p2 = (char *)malloc(4096); memset(p2, 'b', 4096); printf("p1 is %c at address %p\n", p1[0], p1); printf("p2 is %c at address &p\n", p2[0], p2); free(p1); /* remapping virtual addresses */ void *p0 = mremap(p2, 4096, 4096, MREMAP_MAYMOVE | MREMAP_FIXED, p1); /* checking */ printf("p0 is %c at address %p\n", p0[c], p0); return 0; }预期输出:p1是地址xxx处的ap2在地址yyy处为bp0是地址xxx处的b
expected output: p1 is a at address xxx p2 is b at address yyy p0 is b at address xxx
推荐答案malloc()返回的地址可能没有页面对齐,因此 mremap()是将 errno 设置为 EINVAL .如果我使用 mmap()而不是 malloc(),并修复代码中的语法错误:
The addresses returned by malloc() are probably not page-aligned, so mremap() is setting errno to EINVAL. If I use mmap() instead of malloc(), and fix the syntax errors in your code:
#define _GNU_SOURCE 1 #include <stdio.h> #include <stdlib.h> #include <string.h> #include <sys/mman.h> int main(void) { char *p1 = mmap(NULL, 4096, PROT_READ | PROT_WRITE, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0); memset(p1, 'a', 4096); char *p2 = mmap(NULL, 4096, PROT_READ | PROT_WRITE, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0); memset(p2, 'b', 4096); printf("p1 is %c at address %p\n", p1[0], (void *)p1); printf("p2 is %c at address %p\n", p2[0], (void *)p2); void *p0 = mremap(p2, 4096, 4096, MREMAP_MAYMOVE | MREMAP_FIXED, p1); if ( p0 == MAP_FAILED ) { perror("mremap: mremap failed"); return EXIT_FAILURE; } printf("p0 is %c at address %p\n", ((char *)p0)[0], p0); return EXIT_SUCCESS; }然后我得到:
paul@local:~/src/c/scratch$ ./mremap p1 is a at address 0x7f5addb71000 p2 is b at address 0x7f5addb70000 p0 is b at address 0x7f5addb71000 paul@local:~/src/c/scratch$更多推荐
使用mremap进行内存重新分配
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