使用strcat的不工作追加字符数组

本文介绍了使用strcat的不工作追加字符数组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

能否有人告诉我有什么不对的code ???

字符的短信[] =GR8;strcat的（短信，＆安培; :)）;

解决方案

短信是大小的数组 4 1 。而你更追加字符文字，这是怎么回事阵列之外，作为数组可以在最大 4 这已经是由占据容纳的字符G，R，8，\\ 0 。

1。顺便说一句，到底为什么4？答：因为有在最后一个空字符！

如果你提到数组的大小，如下图所示，那么你的code是有效的和明确的。

字符的短信[10] =GR8; //确保数组的大小为10                       //所以可以几个字符后追加。strcat的（短信，＆安培; :)）;

但随后C ++为您提供更好的解决方案：使用的std ::字符串为：

的#include＆LT;串GT; //必须标准::字符串短信=GR8;短信+ =＆放大器; :) //字符串连接 - 轻松，可爱！

Can some one tell me what's wrong with this code???

char sms[] = "gr8"; strcat (sms, " & :)");

解决方案

sms is an array of size 4 1. And you're appending more char literals, which is going outside of the array, as the array can accommodate at max 4 chars which is already occupied by g, r, 8, \0.

1. By the way, why exactly 4? Answer : Because that there is a null character at the end!

If you mention the size of array as shown below, then your code is valid and well-defined.

char sms[10] = "gr8"; //ensure that size of the array is 10 //so it can be appended few chars later. strcat (sms, " & :)");

But then C++ provides you better solution: use std::string as:

#include <string> //must std::string sms = "gr8"; sms += " & :)"; //string concatenation - easy and cute!