我有一个特定大小的数组(例如100),它是用户输入填充的。但是,用户可能不一定输入足够的数据来填充整个数组。
我想计算用户输入的数组元素。我怎么能做到这一点?
我试过这个for循环:
int COUNT = 0; for(int i = 0; i< size; i ++) if(Student [i] = 1)//表示这个元素是真的,不是空元素。 COUNT ++; cout<< COUNT + 1<< \\\;但是这段代码给出了这一行的错误: $ b $如果(Students [i] == 1)
另外,如果用户输入重复的元素,我只是想计算独特的元素(每次计数一次)。
我的代码是:
#include< iostream> #include< string> #include< sstream> #include< math.h> #define大小100 使用namespace std; int main() { string Students_; 字符串word2; getline(cin,Students_); int k; int l; k = Students_.find([); Students_erase(0,k + 1); l = Students_.find(]); string line2 = Students_.erase(l); stringstream iss(line2); string学生[size]; int counter = 0; while(getline(iss,word2,';')&& amp; counter< size){学生[counter ++] = word2; } int COUNT = 0; for(int i = 0; i< size; i ++) if(Students [i] == 1) COUNT ++; cout<< COUNT + 1<< \\\; 返回0; $ / code>输入例如是: $ b伊斯梅尔·赛义德(Ismail Said)8336,伊斯兰教的说法,(ARC135,ARC114,ARC134,ARC135),8256,埃斯拉说,(ARC134,ARC135,ARC114); 8336, (ARC134,ARC135,ARC114); 8285,Ismail Adballah(ARC114,ARC135,ARC134,ARC114); 8349,Esraa Kassem(ARC135,ARC114,ARC134); 8505,Bassant Kassem(ARC114,ARC135,ARC134,ARC114) ; 8381,Ismail Kassem(ARC135,ARC134,ARC114,ARC135); 8360,Bassant AbdAlrahman(ARC114); 8498,Mohamed Kamal(ARC135,ARC114,ARC134); 8255,Ali Bassem(ARC114,ARC135) (ARC135); 8524,乌萨马·阿巴拉(ARC114,ARC135); 8334,Osama Kamal(ARC114,ARC135,ARC134); 8501,Esraa Tarek(ARC135,ARC134); 8394,Ahmed Zain(ARC134 ,ARC135)]
输入不是常量,只是一个例子。 $ b
解决方案尝试 sizeof(array)/ sizeof(array [0])
在C ++中,总是使用 std :: vector 。有几个内置的函数和一个扩展的功能。 $ b $ p (是的, p> I have an array with a particular size (100 for example), which is filled with user input. However, the user might not necessarily enter enough data to fill the entire array. I want to count the elements of the array which the user entered. How can I do this? I tried by this for loop: But this code gives an error on this line: if (Students[i]==1) Also, if the user enters repeated elements, I just want to count the unique elements (count each value one time). My code is: The input for example is: The input is not constant, it's just an example. Try sizeof(array)/sizeof(array[0]) In C++ always use std::vector. There are several inbuilt functions and an extended functionality. std::vector has a method size() which returns the number of elements in the vector. (Yes, this is tongue-in-cheek answer)
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