如何用？初始化结构数组？(How to initialize array of structures with?)

如何用？初始化结构数组？(How to initialize array of structures with?) struct SampleStruct { int a; int b; float c; double d; short e; };

对于像这样的数组，我曾经用它初始化如下：

struct SampleStruct sStruct = {0};

我想知道当我声明这个结构的数组时，我认为这是正确的

struct SampleStruct sStructs[3] = {{0},{0},{0}};

但是，下面也被编译器接受了

struct SampleStruct sStructs[3] = {0};

我想知道最好，最安全的方法和详细原因。

struct SampleStruct { int a; int b; float c; double d; short e; };

For an array like this, I used to initialize it as below:

struct SampleStruct sStruct = {0};

I would like to know when I declare array of this structure, I thought this will be correct

struct SampleStruct sStructs[3] = {{0},{0},{0}};

But, below also got accepted by the compiler

struct SampleStruct sStructs[3] = {0};

I would like to know the best and safe way and detailed reason why so.

最满意答案

$ gcc --version gcc (GCC) 4.6.1 20110819 (prerelease)

如果使用-Wall选项，我的gcc会给出关于第三个的警告：

try.c:11:9: warning: missing braces around initializer [-Wmissing-braces] try.c:11:9: warning: (near initialization for ‘sStruct3[0]’) [-Wmissing-braces]

指示您应该为初始化编写= {{0}} ，这会将第一个结构的第一个字段设置为0，并将所有其余字段隐式设置为0。 该程序在这个简单的情况下给出了正确的结果，但我认为你不应该依赖于这个并且需要正确地初始化事物。

$ gcc --version gcc (GCC) 4.6.1 20110819 (prerelease)

If using -Wall option, my gcc gives me warnings about the third one:

try.c:11:9: warning: missing braces around initializer [-Wmissing-braces] try.c:11:9: warning: (near initialization for ‘sStruct3[0]’) [-Wmissing-braces]

indicating that you should write = {{0}} for initialization, which set the first field of the first struct to 0 and all the rest to 0 implicitly. The program gives correct result in this simple case, but I think you shouldn't rely on this and need to initialize things properly.