本文介绍了根据距A点的距离在线找到B点的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有线方程,点A和距离,并且需要在距离的边缘找到点B.我有2个方程:
I have line-equation, point-A and distance, and need to find point-B at the edge of the distance, on the line. I have 2 equations:
distance = math.sqrt((pt1[0] - pt2[0])**2 + (pt1[1] - pt2[1])**2) pt2[1] = m*pt2[0] + n距离,pt1,m和n是已知的.
distance, pt1, m and n are known.
如何在Python中实现此计算?也许有一个Python库可以为我做到这一点?
How can I implement this calculation in Python? Maybe there is a Python library that can do this for me?
推荐答案给出线 y = mx + b ,斜率 m 告诉我们变化之间的比率在x( dx )中显示,在y( dy )中变化.
Given the line y=mx+b, the slope m tells us the ratio between the change in x (dx) and the change in y (dy).
数学:
// Given point_b = (point_a[0]+dx,point_a[1]+dy) other_possible_point_b = (point_a[0]-dx,point_a[1]-dy) dy = m*dx x**2 + y**2 = distance // Calculations dx**2 + (m*dx)**2 = distance (m**2+1)(dx**2) = distance dx = sqrt(distance/(m**2+1)) dy = m*sqrt(distance/(m**2+1))Python解决方案:
Python solution:
from math import sqrt point_b = (point_a[0]+dx(distance,m), point_a[1]+dy(distance,m)) other_possible_point_b = (point_a[0]-dx(distance,m), point_a[1]-dy(distance,m)) # going the other way def dy(distance, m): return m*dx(distance, m) def dx(distance, m): return sqrt(distance/(m**2+1))更多推荐
根据距A点的距离在线找到B点
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